7x^2+23x+11=0

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Solution for 7x^2+23x+11=0 equation:



7x^2+23x+11=0
a = 7; b = 23; c = +11;
Δ = b2-4ac
Δ = 232-4·7·11
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{221}}{2*7}=\frac{-23-\sqrt{221}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{221}}{2*7}=\frac{-23+\sqrt{221}}{14} $

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